6-4x-x^2=x^2+16

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Solution for 6-4x-x^2=x^2+16 equation: 



6-4x-x^2=x^2+16

We move all terms to the left:

6-4x-x^2-(x^2+16)=0

We add all the numbers together, and all the variables

-1x^2-4x-(x^2+16)+6=0

We get rid of parentheses

-1x^2-x^2-4x-16+6=0

We add all the numbers together, and all the variables

-2x^2-4x-10=0

a = -2; b = -4; c = -10;
Δ = b2-4ac
Δ = -42-4·(-2)·(-10)
Δ = -64
Delta is less than zero, so there is no solution for the equation

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